Calculate the mole fraction of benzene in solution containing 30% by mass in carbon
tetrachloride.
Solution - 30% by mass of C6H6 in CCl4 = 30 g C6H6 in 100 g solution
Therefore, Number of moles of C6H6 = 30/78 = 0.385 mol (Molar mass of C6H6 = 78)
and No. of moles of CCl4 = 70/154 = 0.455 (Molar mass of CCl4 = 154)
Therefore,
Mole Fraction of C6H6 = Moles of C6H6/Total Moles = 0.385/(0.385+0.455) = 0.458
Mole Fraction of CCl4 = 1 - 0.458 = 0542